Formula 1 point When 8.43 liters of chlorine gas is added to aluminum metal how many grams of Aluminum chloride is produced? underline ( )Al +underline ( )Cl_(2) arrow underline ( )AlCl_(3) Type your answer...

## Step 1The balanced chemical equation for the reaction between aluminum and chlorine gas is:### This equation tells us that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride.## Step 2We are given that 8.43 liters of chlorine gas is used. We need to convert this volume to moles using the ideal gas law, which states that 1 mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters.## Step 3So, the number of moles of chlorine gas is:### ## Step 4From the balanced chemical equation, we know that 3 moles of chlorine gas produce 2 moles of aluminum chloride. Therefore, 0.375 moles of chlorine gas will produce:### ## Step 5The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol. Therefore, the mass of aluminum chloride produced is:###