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Current Attempt in Progress Let T Be the Number of Years Since Farming Began in a Region . The Number, N, of Acres of Harvested Land at

Problemas

Current Attempt in Progress Let t be the number of years since farming began in a region . The number, N, of acres of harvested land at time tis given by N=f(t)=150sqrt (t) Find f(25)cdot f'(25) and the relative rate of change (f')/(f) at t=25. Interpret your answers in terms of harvested land. Enter exact answers. f(25)=boxed (1) f'(25)=boxed (1) (f'(25))/(f(25))=boxed (1)

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Respuesta

\(f(25)=150\sqrt{25}=375\)\(f'(25)=\frac{150}{2\sqrt{25}}=15\)\(\frac{f'(25)}{f(25)}=\frac{15}{375}=0.04\)So, the answers are \(f(25)=375\), \(f'(25)=15\), and \(\frac{f'(25)}{f(25)}=0.04\).

Explicación

## Step 1The problem provides a function \(N=f(t)=150\sqrt{t}\), which represents the number of acres of harvested land at time . We are asked to find the values of \(f(25)\), \(f'(25)\), and the relative rate of change at .## Step 2First, we need to find the value of \(f(25)\). This is done by substituting into the function \(f(t)\).### \(f(25)=150\sqrt{25}\)## Step 3Next, we need to find the derivative of \(f(t)\), which is \(f'(t)\). The derivative of a function gives us the rate of change of the function at any given point.### \(f'(t)=\frac{150}{2\sqrt{t}}\)## Step 4Now, we substitute into \(f'(t)\) to find \(f'(25)\).### \(f'(25)=\frac{150}{2\sqrt{25}}\)## Step 5Finally, we calculate the relative rate of change at .### \(\frac{f'(25)}{f(25)}=\frac{\frac{150}{2\sqrt{25}}}{150\sqrt{25}}\)