Multiple Choice 10 points 4Fe+3O_(2)... 2Fe_(2)O_(3) How many grams of Fe_(2)O_(3) can be produced when 1.84 moles of O_(2) reacts with excess iron (Fe)? 3928 6.12g 39.3g 1968

Question

Answer 1

This is a stoichiometry problem. The balanced chemical equation is given as

. From this equation, we can see that 3 moles of

react with 4 moles of

to produce 2 moles of

. Therefore, the molar ratio of

to

is 3:2. Given that 1.84 moles of

are reacting, we can calculate the moles of

produced by multiplying 1.84 by 2/3, which gives us 1.2267 moles of

. The molar mass of

is 159.69 g/mol, so the mass of

produced is 1.2267 moles * 159.69 g/mol = 196.8 g. Therefore, the answer is 1968g.

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