Question to (1 point) Judy has a mass of 35Kg and is roller skating with a volocity of 4m/s. Jimmy skates up behind her and pushes her, increasing her volocity to 5.5m/s How much work did Jimmy accomplish? a 5323. b 249.4. 184J d 1.5 J

## Step 1The work done on an object is equal to the change in its kinetic energy. This is based on the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.## Step 2The formula for kinetic energy is given by:### where is the mass of the object and is its velocity.## Step 3Calculate the initial kinetic energy of Judy. Substituting the given values into the formula, we get:### \( KE_{initial} = \frac{1}{2} \times 35 \, kg \times (4 \, m/s)^2 = 280 \, J \)## Step 4Calculate the final kinetic energy of Judy after Jimmy pushed her. Substituting the given values into the formula, we get:### \( KE_{final} = \frac{1}{2} \times 35 \, kg \times (5.5 \, m/s)^2 = 538.75 \, J \)## Step 5The work done by Jimmy is the difference between the final and initial kinetic energies. So, we subtract the initial kinetic energy from the final kinetic energy to get the work done by Jimmy.###