Answer in units of mm. 002 (part 1 of 2) 10.0 points How much pressure is applied to the ground by a 109 kg man who is standing on square stilts that measure 0 .06 m on each edge? Answer in units of Pa. 003 (part 2 of 2)10.0 points What is this pressure in pounds per square inch? Answer in units of lb/in^2

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Answer in units of mm. 002 (part 1 of 2) 10.0 points How much pressure is applied to the ground by a 109 kg man who is standing on square stilts that measure 0 .06 m on each edge? Answer in units of Pa. 003 (part 2 of 2)10.0 points What is this pressure in pounds per square inch? Answer in units of lb/in^2

Answer 1

To solve this problem, we need to calculate the pressure applied to the ground by the man standing on the stilts.Given information:- Mass of the man: 109 kg- Length of each stilt: 0.06 mStep 1: Calculate the total area of the stilts.Total area = 2 × (length of each stilt)^2Total area = 2 × (0.06 m)^2 = 0.0072 m^2Step 2: Calculate the pressure applied to the ground.Pressure = Force / AreaForce = Mass × Acceleration due to gravityForce = 109 kg × 9.8 m/s^2 = 1072.2 NPressure = 1072.2 N / 0.0072 m^2 = 14883.33 PaTherefore, the pressure applied to the ground by the man standing on the stilts is 14883.33 Pa.To convert this pressure to pounds per square inch (lb/in^2), we need to use the conversion factor:1 Pa = 0.000145038 lb/in^2Pressure in lb/in^2 = 14883.33 Pa × 0.000145038 lb/in^2 = 2.16 lb/in^2Therefore, the pressure applied to the ground by the man standing on the stilts is 2.16 lb/in^2.

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