In an experiment, a student added a specified amount of sodium chloride to 101 of water in A different beakers.The amount of in each beaker is listed below. Beaken A: 2.5 g cf NaCl in 10 L of water Beaker B: 156 got NaCl mill of water Beaker C: 0.75 cf NaCl in 10 L of matter Beaker 0:413 g cf NaCl in 10 L of water What is the concentration (in molarity) of the solution in Beaker D? 0.214 0.07 M 20

Question

In an experiment, a student added a specified amount of sodium chloride to 101 of water in A different beakers.The amount of in each beaker is listed below. Beaken A: 2.5 g cf NaCl in 10 L of water Beaker B: 156 got NaCl mill of water Beaker C: 0.75 cf NaCl in 10 L of matter Beaker 0:413 g cf NaCl in 10 L of water What is the concentration (in molarity) of the solution in Beaker D? 0.214 0.07 M 20

Answer 1

To calculate the concentration of the solution in Beaker D, we need to use the formula for molarity:Molarity (M) = moles of solute / liters of solutionGiven information:- Beaker D contains 41.35 g of NaCl dissolved in 10 L of water.Step 1: Calculate the moles of NaCl in Beaker D.Moles of NaCl = Mass of NaCl / Molar mass of NaClMolar mass of NaCl = 58.44 g/molMoles of NaCl = 41.35 g / 58.44 g/mol = 0.710 molStep 2: Calculate the molarity of the solution in Beaker D.Molarity (M) = moles of solute / liters of solutionMolarity (M) = 0.710 mol / 10 L = 0.071 MTherefore, the concentration (in molarity) of the solution in Beaker D is 0.071 M.

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