Problemas
Avogadro's Law (V_(1)/n_(1)=V_(2)/n_(2)) 11. A gas sample contains 2.0 moles and occupies 44.8 L. How much volume would it occupy if the number of moles increases to 4.0 moles? 12. A gas occupies 11.2 L with 0.5 moles of gas. How many moles would be required to expand it to 44.8 L? 13. A balloon with 3.0 moles of gas has a volume of 67.2 L. What is the new volume if the number of moles are increased to 6.0 moles of gas? 14. If a gas sample with 4.0 moles occupies 89.6 L, how many moles would be present in 22.4 L? 15. A gas has a volume of 33.6 L when it contains 1.5 moles. What is the volume if the amount of gas is reduced to 0.5 moles?
Roztwór
Rafael
élite · Tutor durante 8 años
4.1
(185 Votos)
Respuesta
11. According to Avogadro's Law, the volume of a gas is directly proportional to the number of moles of gas, provided the temperature and pressure remain constant. In this case, the number of moles increases from 2.0 to 4.0, which is a doubling. Therefore, the volume will also double. So, the new volume would be 44.8 L * 2 = 89.6 L.12. Using Avogadro's Law again, we can set up the equation 11.2 L / 0.5 moles = 44.8 L / x moles. Solving for x, we get x = (44.8 L * 0.5 moles) / 11.2 L = 2.0 moles.13. In this case, the number of moles increases from 3.0 to 6.0, which is a doubling. Therefore, the volume will also double. So, the new volume would be 67.2 L * 2 = 134.4 L.14. Using Avogadro's Law, we can set up the equation 89.6 L / 4.0 moles = 22.4 L / x moles. Solving for x, we get x = (22.4 L * 4.0 moles) / 89.6 L = 1.0 moles.15. Using Avogadro's Law, we can set up the equation 33.6 L / 1.5 moles = x L / 0.5 moles. Solving for x, we get x = (33.6 L * 0.5 moles) / 1.5 moles = 11.2 L.