Question 1-3 TRAVEL Stacy flew an airplane for 2 hours at x miles per hour, and then she flew another 3 hours at (x+25) miles per hour. The entire distance she flow was 1000 miles Stacy flew at a rate of square miles per hour for 2 hours and square - miles per hour for 3 hours

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Question 1-3 TRAVEL Stacy flew an airplane for 2 hours at x miles per hour, and then she flew another 3 hours at (x+25) miles per hour. The entire distance she flow was 1000 miles Stacy flew at a rate of square miles per hour for 2 hours and square - miles per hour for 3 hours

Answer 1

To solve this problem, we need to find the values of x and (x+25) that satisfy the given conditions.Given information:- Stacy flew an airplane for 2 hours at x miles per hour.- She then flew another 3 hours at (x+25) miles per hour.- The entire distance she flew was 1000 miles.Let's denote the distance Stacy flew at x miles per hour as D1 and the distance she flew at (x+25) miles per hour as D2.We can use the formula: Distance = Speed × Time to find the values of D1 and D2.D1 = x × 2D2 = (x+25) × 3The total distance Stacy flew is the sum of D1 and D2, which is 1000 miles.D1 + D2 = 1000x × 2 + (x+25) × 3 = 1000Simplifying the equation:2x + 3(x+25) = 10002x + 3x + 75 = 10005x + 75 = 10005x = 925x = 185Therefore, Stacy flew at a rate of 185 miles per hour for 2 hours and (185+25) = 210 miles per hour for 3 hours.

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Question 1-3 TRAVEL Stacy flew an airplane for 2 hours at x miles per hour, and then she flew another 3 hours at (x+25) miles per hour. The entire distance she flow was 1000 miles Stacy flew at a rate of square miles per hour for 2 hours and square - miles per hour for 3 hours

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