Problemas
Match each atomic bond to its bond type Use an electronegativity chart to solve for the difference between the atoms. Non-polar Covalent lenle Polar Covalent C-H Na-F C-F
Roztwór
Norma
professionell · Tutor durante 6 años
4.1
(324 Votos)
Respuesta
C-H: Non-polar CovalentNa-F: IonicC-F: Polar Covalent
Explicación
## Step 1: Understanding the concept of electronegativityElectronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. The Pauling scale is used to measure electronegativity values, with higher values indicating greater electronegativity.## Step 2: Determining the bond type based on electronegativity differenceThe bond type can be determined by calculating the difference in electronegativity values between the two atoms involved in the bond. ### Non-polar Covalent Bond:A non-polar covalent bond occurs when the electronegativity difference between the two atoms is less than 0.5. In this case, the electrons are shared equally between the atoms.### Polar Covalent Bond:A polar covalent bond occurs when the electronegativity difference between the two atoms is between 0.5 and 1.7. In this case, the electrons are shared unequally, with one atom attracting the electrons more strongly than the other.### Ionic Bond:An ionic bond occurs when the electronegativity difference between the two atoms is greater than 1.7. In this case, one atom donates an electron to the other atom, resulting in the formation of positively and negatively charged ions.## Step 3: Calculating the electronegativity difference for each bondUsing an electronegativity chart, we can calculate the electronegativity difference for each bond:### C-H Bond:The electronegativity of carbon (C) is 2.55, and the electronegativity of hydrogen (H) is 2.2. Electronegativity difference = 2.55 - 2.2 = 0.35### Na-F Bond:The electronegativity of sodium (Na) is 0.93, and the electronegativity of fluorine (F) is 3.98.Electronegativity difference = 3.98 - 0.93 = 3.05### C-F Bond:The electronegativity of carbon (C) is 2.55, and the electronegativity of fluorine (F) is 3.98.Electronegativity difference = 3.98 - 2.55 = 1.43## Step 4: Determining the bond type based on the electronegativity differenceBased on the calculated electronegativity differences, we can determine the bond type for each bond:### C-H Bond:Since the electronegativity difference is 0.35, which is less than 0.5, the C-H bond is a non-polar covalent bond.### Na-F Bond:Since the electronegativity difference is 3.05, which is greater than 1.7, the Na-F bond is an ionic bond.### C-F Bond:Since the electronegativity difference is 1.43, which is between 0.5 and 1.7, the C-F bond is a polar covalent bond.