The electrolysis of water forms H_(2) and O_(2) 2H_(2)Oarrow 2H_(2)+O_(2) What is the percent yield of O_(2) if 10.2 g of O_(2) is produced from the decomposition of 17.0 g of H_(2)O Use % Yield=(Actualyield)/(Theoreticalyield)times 100 15.1% 33.8% 60.1% 67.6%

Question

Answer 1

To calculate the percent yield of

, we first need to determine the theoretical yield of

based on the given amount of

.Step 1: Calculate the molar mass of

.The molar mass of

is 18.01528 g/mol.Step 2: Calculate the number of moles of

.Number of moles of

=

= 0.943 molesStep 3: Use the stoichiometry of the reaction to find the theoretical yield of

.According to the balanced equation, 2 moles of

produce 1 mole of

. Therefore, 0.943 moles of

will produce 0.4715 moles of

.Step 4: Calculate the theoretical yield of

in grams.The molar mass of

is 31.998 g/mol.Theoretical yield of

= 0.4715 moles * 31.998 g/mol = 15.1 gStep 5: Calculate the percent yield of

.Percent yield =

= 67.6%Therefore, the correct answer is

.

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