Find the equation of a line perpendicular to y=-x-1 that passes through the point (2,9)

To find the equation of a line perpendicular to that passes through the point , we need to determine the slope of the perpendicular line.The slope of the given line is . The slope of a line perpendicular to this line is the negative reciprocal of , which is .Now, we can use the point-slope form of a linear equation to find the equation of the perpendicular line. The point-slope form is given by: where is a point on the line and is the slope.Substituting the given point and the slope into the equation, we have: Simplifying this equation, we get: Therefore, the equation of the line perpendicular to that passes through the point is .