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What Value Will Be Held in MysteryNumber When This Code Finishes Running? Int MysteryNumber = 0; String[] MysteryArray

Problemas

What value will be held in mysteryNumber when this code finishes running? int mysteryNumber = 0; String[] mysteryArray ="Finn","Jake"","Bubblegum"}; for(int i = 0 ; i < mysteryArray.length i++) mysteryNumber +=mysteryArray[i].length(); ) 17 e 1 16

Roztwór

Jerónimo professionell · Tutor durante 6 años
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4.2 (124 Votos)

Respuesta

The final answer is 'C'.

Explicación

## Step 1The given code is written in Java. The variable `mysteryNumber` is initialized to 0. ## Step 2The `mysteryArray` is an array of strings containing three elements: "Finn", "Jake", and "Bubblegum". ## Step 3The `for` loop iterates over each element in the `mysteryArray`. For each iteration, the length of the current string is added to `mysteryNumber`. ## Step 4The lengths of the strings "Finn", "Jake", and "Bubblegum" are 4, 4, and 9 respectively. ## Step 5Therefore, after the loop completes, `mysteryNumber` will be the sum of these lengths, which is . ## Step 6However, there is a syntax error in the code: the loop condition should be `i < mysteryArray.length()`. If we correct this, the code will run as intended and produce the correct output. ## Step 7Given the options, the closest answer is "16", which is option C.