A potter's wheel moves from rest to an angular speed of 0.10rev/s in 31.5 s. Assuming constant angular acceleration, what is its angular acceleration in rad/s^2 Answer in units of rad/s^2 Answer in units of rad/s^2

Question

A potter's wheel moves from rest to an angular speed of 0.10rev/s in 31.5 s. Assuming constant angular acceleration, what is its angular acceleration in rad/s^2 Answer in units of rad/s^2 Answer in units of rad/s^2

Answer 1

To find the angular acceleration, we can use the formula:Angular acceleration = (Final angular velocity - Initial angular velocity) / TimeFirst, we need to convert the final angular velocity from rev/s to rad/s:Final angular velocity = 0.10 rev/s * 2π rad/rev = 0.20π rad/sNow we can calculate the angular acceleration:Angular acceleration = (0.20π rad/s - 0 rad/s) / 31.5 sAngular acceleration = 0.20π / 31.5 rad/s²Angular acceleration ≈ 0.020 rad/s²Therefore, the angular acceleration of the potter's wheel is approximately 0.020 rad/s².

Problemas

A potter's wheel moves from rest to an angular speed of 0.10rev/s in 31.5 s. Assuming constant angular acceleration, what is its angular acceleration in rad/s^2 Answer in units of rad/s^2 Answer in units of rad/s^2

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