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Amonton's Law Calculations 1. Determine the Pressure Change When a Constant Volume of a Gas at 101.3 KPa Is Heated from 25^circ C to

Problemas

Amonton's Law Calculations 1. Determine the pressure change when a constant volume of a gas at 101.3 kPa is heated from 25^circ C to 35^circ C 2. A gas has a pressure of 794 mm Hg at 43^circ C What is the temperature at standard pressure? 3. If a gas in a closed container is pressurized from 12.0 atm to 25.0 atm and its origir temperature was 32.0^circ C what would the final temperature of the gas be? 4. A sample of gas at 3000 mm Hg inside a steel tank is cooled from 500^circ C to 0^circ What is the final pressure of the gas in the steel tank? (P_(1))/(T_(1))=(P_(2))/(T_(2))

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Hugo maestro · Tutor durante 5 años
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Respuesta

1. To determine the pressure change when a constant volume of a gas at 101.3 kPa is heated from to , we can use the formula for Amonton's Law: where is the initial pressure, is the initial temperature in Kelvin, is the final pressure, and is the final temperature in Kelvin.First, we need to convert the temperatures from Celsius to Kelvin by adding 273.15: Now we can plug in the values into the formula: Solving for , we get: Therefore, the pressure change when the gas is heated from to is approximately 3.3 kPa.2. To find the temperature at standard pressure for a gas with a pressure of 794 mm Hg at , we can use the same formula for Amonton's Law: First, we need to convert the pressure from mm Hg to atm by dividing by 760: Now we can plug in the values into the formula: Solving for , we get: Therefore, the temperature at standard pressure for the gas with a pressure of 794 mm Hg at is approximately 303.15 K.3. To find the final temperature of a gas when pressurized from 12.0 atm to 25.0 atm and its original temperature was , we can use the same formula for Amonton's Law: First, we need to convert the temperature from Celsius to Kelvin by adding 273.15: Now we can plug in the values into the formula: Solving for , we get: Therefore, the final temperature of the gas when pressurized from 12.0 atm to 25.0 atm and its original temperature was is approximately 635.29 K.4. To find the final pressure of a sample of gas at 3000 mm Hg inside a steel tank when cooled from to , we can use the same formula for Amonton's Law: First, we need to convert the temperatures from Celsius to Kelvin by adding 273.15: Now we can plug in the values into the formula: Solving for , we get: