When 4256.4 Joules of heat is absorbed, a 150 gram sample of a metal warms from 25.1 degrees Celsius to 65.8 degrees Celsius .What is the specific dot (C)p=(Q)/(m(Delta T)) heat (Cp) of the metal?The formula for calculating specific heat has been given. 0.70(J)/(gcdot ^circ )C 0.6971(J)/(gcdot ^circ )C 0.697(J)/(gcdot ^circ )C 0.7(J)/(gcdot ^circ )C

To find the specific heat ( ) of the metal, we can use the formula provided: where:- is the amount of heat absorbed (4256.4 Joules),- is the mass of the sample (150 grams),- is the change in temperature.First, calculate the change in temperature ( ): Now, substitute the values into the formula: Calculate the denominator: Now, divide the numerator by the denominator: Therefore, the specific heat ( ) of the metal is approximately: The correct answer is: