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A Car Is Traveling at 20.0m/s and Accelerates at 3.00m/s^2 to Pass a Truck. It Takes 15.0 M to Pass the Truck. How Fast Is the Car

Problemas

A car is traveling at 20.0m/s and accelerates at 3.00m/s^2 to pass a truck. It takes 15.0 m to pass the truck. How fast is the car traveling after going 15.0 m. 490.m/s 110.m/s 22.1m/s 10.5m/s

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Mario élite · Tutor durante 8 años
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Respuesta

To solve this problem, we can use the kinematic equation that relates initial velocity, acceleration, distance, and final velocity:v^2 = u^2 + 2asWhere:v = final velocityu = initial velocitya = accelerations = distanceGiven information:- Initial velocity (u) = 20.0 m/s- Acceleration (a) = 3.00 m/s^2- Distance (s) = 15.0 mSubstituting the values in the equation:v^2 = (20.0 m/s)^2 + 2 × (3.00 m/s^2) × (15.0 m)v^2 = 400 m^2/s^2 + 90 m^2/s^2v^2 = 490 m^2/s^2v = √(490 m^2/s^2)v = 22.1 m/sTherefore, the car is traveling at 22.1 m/s after going 15.0 m.The correct answer is 22.1 m/s.