Question 5 (1 point) You have 0.5 L of air at 203 K in an expandable container at constant pressure. You heat the container to 273 K. What is the volume of air? (V_(1))/(T_(1))=(V_(2))/(T_(2)) V_(1)=0.5L T_(1)=203K V_(2)=? T_(2)=273K Hint: there is an example problem in your student notes. (Charles Law) 0.67 L ) 0.37 L ) 0.25 L 1.5 L

To solve this problem, we will use Charles' Law, which states that the volume of a gas is directly proportional to its temperature when pressure is held constant. The formula for Charles' Law is: Given:- L- K- KWe need to find .Rearrange the formula to solve for : Substitute the given values into the equation: Calculate the value: Rounding to two decimal places, we get: Therefore, the volume of air at 273 K is approximately 0.67 L.The correct answer is:0.67