Two 10 ohms resistors are connected in series to a 12 V battery. Calculate the voltage drop and current across one of the 10 Ohm resistor 6 V, 0.6 A 8V, 0.6 A 1.2V,2 A 12V.12 A

Question

Two 10 ohms resistors are connected in series to a 12 V battery. Calculate the voltage drop and current across one of the 10 Ohm resistor 6 V, 0.6 A 8V, 0.6 A 1.2V,2 A 12V.12 A

Answer 1

To solve this problem, we need to use Ohm's Law and the concept of series circuits.Given information:- Two 10 ohms resistors are connected in series to a 12 V battery.Step 1: Calculate the total resistance in the series circuit.Total resistance = R1 + R2 = 10 ohms + 10 ohms = 20 ohmsStep 2: Calculate the current flowing through the circuit.Current (I) = Voltage (V) / Total resistance (R)I = 12 V / 20 ohms = 0.6 AStep 3: Calculate the voltage drop across one of the 10 ohm resistors.Voltage drop (V) = Current (I) × Resistance (R)V = 0.6 A × 10 ohms = 6 VTherefore, the voltage drop across one of the 10 ohm resistors is 6 V, and the current flowing through the resistor is 0.6 A.The correct answer is:6 V, 0.6 A

Problemas

Two 10 ohms resistors are connected in series to a 12 V battery. Calculate the voltage drop and current across one of the 10 Ohm resistor 6 V, 0.6 A 8V, 0.6 A 1.2V,2 A 12V.12 A

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