You have 7,160 grams of a radioactive kind of bismuth. How much will be left after 10 days if its half-life is 5 days? square grams

## Step 1The problem involves the concept of half-life in radioactive decay. The half-life of a radioactive substance is the time it takes for half of the substance to decay. In this case, the half-life of the radioactive bismuth is given as 5 days.## Step 2The formula to calculate the remaining amount of a radioactive substance after a certain number of half-lives is:### \(N = N_0 \times (1/2)^{\frac{t}{T}}\)where:- is the remaining amount of the substance,- is the initial amount of the substance,- is the time elapsed,- is the half-life of the substance.## Step 3In this problem, we are given:- grams (the initial amount of bismuth),- days (the time elapsed),- days (the half-life of the bismuth).## Step 4Substituting these values into the formula, we get:### \(N = 7160 \times (1/2)^{\frac{10}{5}}\)## Step 5Simplifying the above expression, we get:### \(N = 7160 \times (1/2)^2\)## Step 6Further simplifying, we get:### ## Step 7Finally, we get:### grams