8. A400 hp engine in a 1,600 kg car applies maximum force for 2 seconds to accelerate the car onto the interstate. It the car moves at 8m/s before accelerating, what is its speed after the 2 seconds of acceleration?

Question

8. A400 hp engine in a 1,600 kg car applies maximum force for 2 seconds to accelerate the car onto the interstate. It the car moves at 8m/s before accelerating, what is its speed after the 2 seconds of acceleration?

Answer 1

To solve this problem, we need to use the principles of Newton's laws of motion and the equations of motion.Given information:- The engine has a power output of 400 hp.- The car has a mass of 1,600 kg.- The car is initially moving at a speed of 8 m/s.- The engine applies maximum force for 2 seconds to accelerate the car.Step 1: Calculate the force applied by the engine.Power = Force × Velocity400 hp = Force × VelocityForce = 400 hp / VelocitySince the engine is applying maximum force, we can assume the velocity is at its maximum value, which is 8 m/s.Force = 400 hp / 8 m/s = 50,000 NStep 2: Calculate the acceleration of the car.Force = Mass × Acceleration50,000 N = 1,600 kg × AccelerationAcceleration = 50,000 N / 1,600 kg = 31.25 m/s²Step 3: Calculate the final speed of the car after 2 seconds of acceleration.Initial velocity (u) = 8 m/sAcceleration (a) = 31.25 m/s²Time (t) = 2 secondsFinal velocity (v) = u + a × tv = 8 m/s + 31.25 m/s² × 2 sv = 8 m/s + 62.5 m/sv = 70.5 m/sTherefore, the speed of the car after 2 seconds of acceleration is 70.5 m/s.

Problemas

8. A400 hp engine in a 1,600 kg car applies maximum force for 2 seconds to accelerate the car onto the interstate. It the car moves at 8m/s before accelerating, what is its speed after the 2 seconds of acceleration?

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