Unit 5 - Part 2 Centripetal acceleration Assessment POSSIBLE POIN VTS: 6.67 What is the centripetal acceleration of an object that is moving around a curve with a radius of 8 m if it completes 4 revolutions in 20 seconds?Hint: Find Period, then use that to find Velocity, then use that to find Acceleration. 0.63m/s2 3.63m/s2 12.63m/s2 30.63m/s2

To find the centripetal acceleration of an object moving around a curve, we can follow these steps:1. Find the period (T) of the motion: The period is the time it takes for the object to complete one revolution. In this case, the object completes 4 revolutions in 20 seconds, so the period is: T = 20 seconds / 4 revolutions = 5 seconds per revolution2. Find the velocity (v) of the object: The velocity can be calculated using the formula: v = 2πr/T where r is the radius of the curve and T is the period. v = 2π * 8 m / 5 s = 8π m/s3. Find the centripetal acceleration (a_c): The centripetal acceleration can be calculated using the formula: a_c = v^2 / r where v is the velocity and r is the radius of the curve. a_c = (8π m/s)^2 / 8 m = 8π^2 m/s^2 ≈ 63.66 m/s^2Therefore, the centripetal acceleration of the object is approximately 63.66 m/s^2, which is closest to the option .