2. Find the molar mass of Mg_(3)(PO_(4))_(2)

To find the molar mass of \( Mg_3(PO_4)_2 \), we need to sum the molar masses of all the atoms in the compound. The compound consists of:- Magnesium (Mg)- Phosphorus (P)- Oxygen (O)The molar masses of these elements are approximately:- Mg: 24.305 g/mol- P: 30.9738 g/mol- O: 16.00 g/molThe formula \( Mg_3(PO_4)_2 \) indicates:- 3 magnesium atoms- 2 phosphate groups ( )Each phosphate group ( ) consists of:- 1 phosphorus atom- 4 oxygen atomsSo, for \( Mg_3(PO_4)_2 \):- Magnesium: g/mol- Phosphorus: g/mol- Oxygen: g/molNow, let's calculate each part:1. Magnesium: g/mol2. Phosphorus: g/mol3. Oxygen: g/molFinally, sum these values to get the molar mass of \( Mg_3(PO_4)_2 \): g/molTherefore, the molar mass of \( Mg_3(PO_4)_2 \) is approximately 262.86 g/mol.