2. An electron with a charge of -1.60times 10^wedge -19C and a mass of 9.11times 10^wedge -31kg is traveling at a speed of 3.0times 10^wedge 7m/s perpendicular to uniform magnetic field of strength 0.2 T. What is the magnitude of the magnetic ......................................................................electron?

To find the magnitude of the magnetic force acting on the electron, we can use the formula: where:- is the magnetic force,- is the charge of the electron,- is the velocity of the electron,- is the magnetic field strength,- is the angle between the velocity and the magnetic field.Since the electron is traveling perpendicular to the magnetic field, the angle is 90 degrees, and \( \sin(90^\circ) = 1 \).Given:- - - Now, plug these values into the formula: The magnitude of the magnetic force is .