A hockey puck is set in motion across a frozen pond. If ice friction and air resistance are neglected the force required to keep the puck sliding at constant velocity is Equal to its weight. Equal to its weight divided by its mass. Equal to its mass times its weight. None of the above Burl and Paul paint signs together on a scaffold. Compared to their weights plus the weight of the scaffold, the sum of tensions in the supporting ropes is Less The same Greater Zero

Question

A hockey puck is set in motion across a frozen pond. If ice friction and air resistance are neglected the force required to keep the puck sliding at constant velocity is Equal to its weight. Equal to its weight divided by its mass. Equal to its mass times its weight. None of the above Burl and Paul paint signs together on a scaffold. Compared to their weights plus the weight of the scaffold, the sum of tensions in the supporting ropes is Less The same Greater Zero

Answer 1

1. The force required to keep the hockey puck sliding at constant velocity is none of the above. According to Newton's first law of motion, an object in motion will stay in motion at a constant velocity unless acted upon by an external force. In this case, if ice friction and air resistance are neglected, there is no external force acting on the puck, so it will continue to slide at a constant velocity without any additional force required.2. The sum of tensions in the supporting ropes compared to their weights plus the weight of the scaffold is the same. In a system where objects are connected by ropes and are in equilibrium, the sum of the tensions in the ropes must equal the sum of the weights of the objects plus any additional forces acting on the system. In this case, the weight of the scaffold is an additional force acting on the system, so the sum of tensions in the ropes must be equal to the sum of their weights plus the weight of the scaffold.

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