The charges q_(1)=10mu C and q_(2)=-5mu C are separated by a distance of 3.00 cm between the centers of their charges. Using Coulomb's law, the distance between the center of charges, and scientific notation, calculate the magnitude of the net electric force on charge 4.99times 10^2 B. 8.99times 10^9 c 6.99times 10^2 D 5.99times 10^9

To calculate the magnitude of the net electric force on the charges, we can use Coulomb's law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.The formula for Coulomb's law is:F = k * (|q1| * |q2|) / r^2Where:- F is the magnitude of the force between the charges- k is the Coulomb constant, which is approximately 8.99 x 10^9 N⋅m^2/C^2- q1 and q2 are the charges- r is the distance between the chargesGiven information:- q1 = 10 μC = 10 x 10^-6 C- q2 = -5 μC = -5 x 10^-6 C- r = 3.00 cm = 0.03 mSubstituting the values into the formula:F = (8.99 x 10^9 N⋅m^2/C^2) * (|10 x 10^-6 C| * |-5 x 10^-6 C|) / (0.03 m)^2F = (8.99 x 10^9 N⋅m^2/C^2) * (50 x 10^-12 C^2) / (0.03 m)^2F = (8.99 x 10^9 N⋅m^2/C^2) * (50 x 10^-12 C^2) / (9 x 10^-4 m^2)F = (8.99 x 10^9 N⋅m^2/C^2) * (50 x 10^-12 C^2) / (9 x 10^-4 m^2)F = 4.99 x 10^2 NTherefore, the magnitude of the net electric force on the charges is 4.99 x 10^2 N.The correct answer is A. .