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What Is the Mass of 040 Mol of Aspirin, C_(9)H_(8)O_(4) 45 G 80g 72g 160g 10.8 G

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What is the mass of 040 mol of aspirin, C_(9)H_(8)O_(4) 45 g 80g 72g 160g 10.8 g

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Respuesta

To find the mass of 0.40 mol of aspirin (C9H8O4), we need to calculate the molar mass of aspirin first.The molar mass of aspirin is calculated by adding the molar masses of each element in the compound:Molar mass of C = 12.01 g/molMolar mass of H = 1.01 g/molMolar mass of O = 16.00 g/molMolar mass of C9H8O4 = (9 * 12.01) + (8 * 1.01) + (4 * 16.00) = 180.16 g/molNow, we can calculate the mass of 0.40 mol of aspirin:Mass = Molar mass * Number of molesMass = 180.16 g/mol * 0.40 molMass = 72.064 gTherefore, the mass of 0.40 mol of aspirin is approximately 72 g.