16Ga+3S8-gt 8Ga2S3 How many moles of Ga2S3 do I get from 4 mol Ga and 4.5 mol S8 2 4 8 12

To determine how many moles of Ga2S3 are produced from 4 moles of Ga and 4.5 moles of S8, we need to use stoichiometry based on the balanced chemical equation: First, identify the limiting reactant by comparing the mole ratio of the reactants to the stoichiometric ratio in the balanced equation.1. Calculate the stoichiometric ratio of Ga to S8: - According to the balanced equation, 16 moles of Ga react with 3 moles of S8. - Therefore, the stoichiometric ratio of Ga to S8 is .2. Compare the actual mole ratio of Ga to S8: - Given: 4 moles of Ga and 4.5 moles of S8. - Calculate the actual ratio: .3. Determine the limiting reactant: - The actual ratio is less than the stoichiometric ratio . - This indicates that Ga is the limiting reactant because there is less Ga available than required for the given amount of S8.4. Calculate the moles of Ga2S3 produced: - According to the balanced equation, 16 moles of Ga produce 8 moles of Ga2S3. - Therefore, 4 moles of Ga will produce moles of Ga2S3.Thus, from 4 moles of Ga and 4.5 moles of S8, you get 2 moles of Ga2S3.The correct answer is: 2