4HfP+3Ru(SO3)2arrow 2Hf2(SO3)3+Ru3P4 How many moles of Ru3P4 do I get from 0.66 mol Ru(SO3)2 0.22 0.66 0.99 1.98

To determine the number of moles of produced from 0.66 moles of \( Ru(SO_3)_2 \), we need to use stoichiometry based on the balanced chemical equation: First, identify the mole ratio between(SO_3)_2 \) and from the balanced equation. According to the equation, 3 moles of \( Ru(SO_3)_2 \) produce 1 mole of .Now, use this ratio to find the number of moles of produced from 0.66 moles of \( Ru(SO_3)_2 \): Therefore, the number of moles of produced from 0.66 moles of \( Ru(SO_3)_2 \) is 0.22 moles.So, the correct answer is: