Problemas
How fast will a 750kg car go if it uses 300,000W of power to accelerate from a speed of 10m/s for 5 seconds? (Hint find work first) W=F(Delta d) P=(WorE)/(t) W=Delta KE=1/2m(v_(f)^2-v_(i)^2) W=Delta PE=mg(h_(f)-h_(i)) WorE=Pt 60,000m/s 80m/s 160m/s 64m/s 8.94m/s
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Alejandra
maestro · Tutor durante 5 años
4.6
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Respuesta
To solve this problem, we need to find the final velocity of the car after it accelerates for 5 seconds using 300,000W of power.Given information:- Mass of the car: 750 kg- Initial velocity: 10 m/s- Power: 300,000 W- Time: 5 secondsStep 1: Calculate the work done by the car.Work done (W) = Change in kinetic energyW = ΔKE = 1/2 m (vf^2 - vi^2)W = 1/2 × 750 kg × (vf^2 - (10 m/s)^2)Step 2: Calculate the power.Power (P) = Work done / TimeP = W / tP = 1/2 × 750 kg × (vf^2 - (10 m/s)^2) / 5 sStep 3: Solve for the final velocity (vf).300,000 W = 1/2 × 750 kg × (vf^2 - (10 m/s)^2) / 5 svf^2 = 160 m^2/s^2vf = √(160 m^2/s^2)vf = 12.65 m/sTherefore, the car will go at a speed of 12.65 m/s after accelerating for 5 seconds using 300,000W of power.