It-Gec-H(g) - 2HK(g)-1-(-f-r-a) Bond: CIC C-C H-I C-I C-H /mol): 839 348 299 240 413 Using the table of average bond energies below the image, tr Delta H for the reaction in kJis __ +160kJ -160kJ -63kJ -217kJ

To calculate the enthalpy change (ΔH) for the reaction, we need to consider the bond energies of the bonds broken and formed during the reaction.Given information:- Bond energies (in kJ/mol): - C-Cl: 339 kJ/mol - C-C: 839 kJ/mol - H-I: 299 kJ/mol -I: 413 kJ/mol - C-H: 348 kJ/molThe reaction is:C2Cl2 + 2HI → 2C2H + 2I2Bonds broken:- 2 C-Cl bonds: 2 × 339 kJ/mol = 678 kJ/mol- 2 H-I bonds: 2 × 299 kJ/mol = 598 kJ/molTotal energy of bonds broken = 678 kJ/mol + 598 kJ/mol = 1,276 kJ/molBonds formed:- 4 C-H bonds: 4 × 348 kJ/mol = 1,392 kJ/mol- 2 C-I bonds: 2 × 413 kJ/mol = 826 kJ/molTotal energy of bonds formed = 1,392 kJ/mol + 826 kJ/mol = 2,218 kJ/molEnthalpy change (ΔH) = Energy of bonds formed - Energy of bonds brokenΔH = 2,218 kJ/mol - 1,276 kJ/mol = 942 kJ/molTherefore, the correct answer is: