C_(2)H_(4)+3O_(2)-2CO_(2)+2H_(2)O Using the equation for the complete combustion of ethene (C_(2)H_(4)) which will be the limiting reactant if equal masses of both ethene and oxygen are provided? Oxygen Not enough information is given. Neither is limiting. d Ethene

To determine the limiting reactant, we need to compare the mole ratio of ethene to oxygen in the balanced chemical equation.The balanced chemical equation for the complete combustion of ethene is: From the equation, we can see that 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 2 moles of water.Now, let's compare the molar masses of ethene and oxygen:Molar mass of ethene (C2H4) = 2(12.01) + 4(1.01) = 28.05 g/molMolar mass of oxygen (O2) = 2(16.00) = 32.00 g/molSince the molar mass of oxygen is greater than the molar mass of ethene, we can conclude that oxygen is the limiting reactant.Therefore, the correct answer is: Oxygen.