Problemas
Ming has two unknown substances. One is nonpolar,and the other is polar. Which process would most likely help Ming identify which substance is polar and which is nonpolar? Test the boiling points The polar substance should have a lower boiling point because of its dipole-dipole forces. Test for an odor The nonpolar substance should have a higher volatility and stronger odor because of its London dispersion forces. Test the boiling points The nonpolar substance should have a higher boiling point because of its hydrogen bonds. Test for an odor.The polar substance should have a higher volatility and weaker odor because of its dipole-dipole forces.
Roztwór
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professionell · Tutor durante 6 años
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Respuesta
The correct answer is 'A'. The most likely process to help Ming identify which substance is polar and which is nonpolar is to test the boiling points. The polar substance should have a lower boiling point due to its dipole-dipole forces.
Explicación
## Step 1The problem involves identifying the nature of two unknown substances, one polar and one nonpolar. The options provided suggest different methods to distinguish between the two substances.## Step 2The first option suggests testing the boiling points. The polar substance should have a lower boiling point due to its dipole-dipole forces. This is a correct statement because polar substances have stronger intermolecular forces, which require more energy (in the form of heat) to break, resulting in a higher boiling point.## Step 3The second option suggests testing for an odor. The nonpolar substance should have a higher volatility and stronger odor due to its London dispersion forces. This is incorrect because nonpolar substances have weaker intermolecular forces, which means they are more volatile and have a stronger odor.## Step 4The third option suggests testing the boiling points again. This time, it suggests that the nonpolar substance should have a higher boiling point due to its hydrogen bonds. This is incorrect because nonpolar substances do not form hydrogen bonds.## Step 5The fourth option suggests testing for an odor again. This time, it suggests that the polar substance should have a higher volatility and weaker odor due to its dipole-dipole forces. This is incorrect because polar substances have stronger intermolecular forces, which means they are less volatile and have a weaker odor.