So __ 9% of the population or 9 out of 100 people have DRY earwax (ww). That means that 91 people out of 100 or 91% have wet earwax right? What 2 pieces of the H-W equation will add up to the 91% (select 2) 2pq p q q^2 p^2

To determine the two pieces of the Hardy-Weinberg equation that add up to 91%, we need to understand the Hardy-Weinberg equilibrium and the allele frequencies.The Hardy-Weinberg equilibrium states that the frequencies of alleles and genotypes in a population remain constant from generation to generation, assuming no mutations, migration, or other evolutionary forces.In this case, we are given that 9% of the population has DRY earwax (ww). This means that the frequency of the recessive allele (q) is 0.09.To find the frequency of the dominant allele (p), we can use the fact that the sum of the frequencies of the dominant and recessive alleles must equal 1:p + q = 1Substituting the value of q, we get:p + 0.09 = 1Solving for p, we find:p = 1 - 0.09 = 0.91Now, we can calculate the frequencies of the heterozygous genotype (2pq) and the homozygous dominant genotype ( ):2pq = 2 * 0.91 * 0.09 = 0.1638 = (0.91)^2 = 0.8281Therefore, the two pieces of the Hardy-Weinberg equation that add up to 91% are:2pq = 0.1638 = 0.8281