EuSe+2Tblarrow Eul2+Tb2Se How many grams of Eul2 do I get from 147.710 poi grams of EuSe? (Eu=152Se=79Tb=159I=127) 259 g 406 g 518g 635g

To solve this problem, we need to use the concept of stoichiometry and the molar masses of the compounds involved.Given information:- The balanced chemical equation is: EuSe + 2TbI → EuI2 + Tb2Se- The molar masses are: Eu = 152, Se = 79, Tb = 159, I = 127- The mass of EuSe is 147.710 gStep 1: Calculate the molar mass of EuSe.Molar mass of EuSe = 152 + 79 = 231 g/molStep 2: Calculate the number of moles of EuSe.Number of moles of EuSe = 147.710 g / 231 g/mol = 0.641 molStep 3: Use the stoichiometry of the balanced equation to find the number of moles of EuI2.According to the balanced equation, 1 mol of EuSe produces 1 mol of EuI2.Number of moles of EuI2 = 0.: Calculate the molar mass of EuI2.Molar mass of EuI2 = 152 + 2(127) = 406 g/molStep 5: Calculate the mass of EuI2 produced.Mass of EuI2 = 0.641 mol × 406 g/mol = 259.686 gTherefore, the correct answer is 259 g.