NSTRUCTIONS Write the procedures and the answers to each exercise. If you he result (without the procedure) your answer will not be valid. Mark your final answers with a different color. Round your answers to two decimal places. .Convert 400 g of Mg(CN)_(2) into mol. Calculate the number of formula units in 600 g of NaNO_(2) . Convert 8.5times 10^27 molecules of KMnO_(4) to grams. Calculate the percent composition of all the elements in: AgH_(2)PO_(4) Convert 2.4times 10^26 molecules of Al_(2)O_(3) to moles

To convert 400 g of into mol:1. Calculate the molar mass of : - Molar mass of Mg = 24.305 g/mol - Molar mass of C = 12.011 g/mol - Molar mass of N = 14.007 g/mol - Molar mass of = 24.305 + 2(12.011 + 14.007) = 92.32 g/mol2. Convert grams to moles: - Moles of = 400 g / 92.32 g/mol = 4.33 molThe final answer is 4.33 mol.To calculate the number of formula units in 600 g of :1. Calculate the molar mass of : - Molar mass of Na = 22.990 g/mol - Molar mass of N = 14.007 g/mol - Molar mass of O = 15.999 g/mol - Molar mass of = 22.990 + 14.007 + 15.999 = 52.996 g/mol2. Convert grams to moles: - Moles of = 600 g / 52.996 g/mol = 11.30 mol3. Calculate the number of formula units: - Number of formula units = 11.30 mol × (6.022 × 10^23 formula units/mol) = 6.82 × 10^24 formula unitsThe final answer is 6.82 × 10^24 formula units.To convert molecules of to grams:1. Calculate the molar mass of : - Molar mass of K = 39.10 g/mol - Molar mass of Mn = 54.938 g/mol - Molar mass of O = 15.999 g/mol - Molar mass of = 39.10 + 54.938 + 4(15.999) = 158.034 g/mol2. Convert molecules to moles: - Moles of = molecules / (6.022 × 10^23 molecules/mol) = 141.5 mol3. Convert moles to grams: - Mass of = 141.5 mol × 158.034 g/mol = 22.34 × 10^3 gThe final answer is 22.34 × 10^3 g.To calculate the percent composition of all the elements in :1. Calculate the molar mass of : - Molar mass of Ag = 107.868 g/mol - Molar mass of H = 1.008 g/mol - Molar mass of P = 30.974 g/mol - Molar mass of O = 15.999 g/mol - Molar mass of = 107.868 + 2(1.008) + 30.974 + 4(15.999) = 207.88 g/mol2. Calculate the percent composition of each element: - Percent composition of Ag = (107.868 / 207.88) × 100% = 51.82% - Percent composition of H = (2 × 1.008 / 207.88) × 100% = 0.97% - Percent composition of P = (30.974 / 207.88) × 100% = 14.88% - Percent composition of O = (4 × 15.999 / 207.88) × 100% = 31.00%The final answer is:- Ag: 51.82%- H: 0.97%- P: 14.88%- O: 31.00%To convert molecules of to moles:1. Calculate the molar mass of : - Molar mass of Al = 26.982 g/mol - Molar mass of O = 15.999 g/mol - Molar mass of $Al_{2}O_{