The chemical equation below is unbalanced. Al(OH)_(3)+H_(2)SO_(4)arrow Al_(2)(SO_(4))_(3)+H_(2)O What is the coefficient of H_(2)O when the equation is correctly balanced using the smallest whole-number coefficients? A. 2 B. 3 C. 4 D. 6

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.Let's start by balancing the aluminum atoms. We have 1 aluminum atom on the left side and 2 aluminum atoms on the right side. To balance the aluminum atoms, we need to put a coefficient of 2 in front of on the left side. Next, let's balance the sulfur atoms. We have 1 sulfur atom on the left side and 3 sulfur atoms on the right side. To balance the sulfur atoms, we need to put a coefficient of 3 in front of on the left side. Finally, let's balance the oxygen atoms. We have 6 oxygen atoms on the left side and 12 oxygen atoms on the right side. To balance the oxygen atoms, we need to put a coefficient of 6 in front of on the right side. Therefore, the coefficient of when the equation is correctly balanced using the smallest whole-number coefficients is 6.The correct answer is D. 6.