Problemas
A player pushes a 250 g hockey puck over frictionless ice with a constant force, causing it to accelerate at 24m/s^2 over a distance of 50.0 cm. a. Find the work done by the hockey player on the puck. (1) Instructions 250 of 250 words remaining square Apply the concept of the conservation of energy using the work-energy theorem to determine the change in the kinetic energy of the puck. I Instructions square
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Felipe
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To find the work done by the hockey player on the puck, we can use the formula:Work = Force x DistanceGiven information:- Mass of the puck = 250 g = 0.25 kg- Acceleration of the puck = 24 m/s²- Distance traveled by the puck = 50.0 cm = 0.5 mStep 1: Calculate the force applied by the player on the puck.Using Newton's second law, we have:Force = Mass x AccelerationForce = 0.25 kg x 24 m/s²Force = 6 NStep 2: Calculate the work done by the player on the puck.Work = Force x DistanceWork = 6 N x 0.5 mWork = 3 JTherefore, the work done by the hockey player on the puck is 3 J.To apply the concept of the conservation of energy using the work-energy theorem, we can use the formula:Work = Change in Kinetic EnergyGiven information:- Mass of the puck = 0.25 kg- Acceleration of the puck = 24 m/s²- Distance traveled by the puck = 0.5 mStep 1: Calculate the initial kinetic energy of the puck.Initial Kinetic Energy = 0 (since the puck starts from rest)Step 2: Calculate the final kinetic energy of the puck.Final Kinetic Energy = 0.5 x Mass x (Acceleration x Distance)²Final Kinetic Energy = 0.5 x 0.25 kg x (24 m/s² x 0.5 m)²Final Kinetic Energy = 0.5 x 0.25 kg x (12 m/s)²Final Kinetic Energy = 0.5 x 0.25 kg x 144 m²/s²Final Kinetic Energy = 18 JStep 3: Calculate the change in kinetic energy of the puck.Change in Kinetic Energy = Final Kinetic Energy - Initial Kinetic EnergyChange in Kinetic Energy = 18 J - 0Change in Kinetic Energy = 18 JTherefore, the change in the kinetic energy of the puck is 18 J.