Problemas
FACTOR each problem as demonstrated in class. Show All WORK! 6. x^2-10x+16 8. 8x^2+14x+3 10. 5x^2+6x-8 9. 5x^2-12x+4
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Antonia
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Let's factor each quadratic expression step by step.### 6.
To factor this quadratic expression, we need to find two numbers that multiply to 16 (the constant term) and add up to -10 (the coefficient of the linear term).The numbers that satisfy these conditions are -2 and -8 because:- \((-2) \times (-8) = 16\)- \((-2) + (-8) = -10\)So, we can write the quadratic expression as:
### 8.
To factor this quadratic expression, we need to find two numbers that multiply to
and add up to 14.The numbers that satisfy these conditions are 12 and 2 because:-
-
We can then rewrite the middle term (14x) using numbers:
Next, we factor by grouping:
### 10.
To factor this quadratic expression, we need to find two numbers that multiply to
and add up to 6.The numbers that satisfy these conditions are 10 and -4 because:- \(10 \times (-4) = -40\)- \(10 + (-4) = 6\)We can then rewrite the middle term (6x) using these two numbers:
Next, we factor by grouping:
### 9.
To factor this quadratic expression, we need to find two numbers that multiply to
and add up to -12.The numbers that satisfy these conditions are -10 and -2 because:- \((-10) \times (-2) = 20\)- \((-10) + (-2) =\)We can then rewrite the middle term (-12x) using these two numbers:
Next, we factor by grouping:
So, the factored forms are:6. \( x^2 - 10x + 16 = (x - 2)(x - 8) \)8. \( 8x^2 + 14x + 3 = (4x + 1)(2x + 3) \)10. \( 5x^2 + 6x - 8 = (5x - 4)(x + 2) \)9. \( 5x^2 - 12x + 4 = (5x - 2)(x - 2) \)