Problemas
LImiting Reactant and Percent Yleld Salicylic acid (C_(7)H_(6)O_(3)) reacts with acetic anhydride (C_(4)H_(6)O_(3)) to form acetylsalicylic aod (C_(9)H_(8)O_(4)) 2C_(7)H_(6)O_(3)(aq)+C_(4)H_(6)O_(3)(aq)arrow 2C_(9)H_(8)O_(4)(aq)+H_(2)O(l) What is the limiting reactant if 700 got C_(7)H_(6)O_(3) and 80.0 g of C_(4)H_(6)O_(3) react? water salicylic acid acetic anhydride acetylsalicylic acid
Roztwór
Maricela
professionell · Tutor durante 6 años
4.2
(250 Votos)
Respuesta
To determine the limiting reactant, we need to compare the amount of each reactant available to the amount required by the stoichiometry of the reaction.First, let's calculate the molar mass of each compound:- Salicylic acid (C7H6O3): 7(12.01) + 6(1.01) + 3(16.00) = 138.12 g/mol- Acetic anhydride (C4H6O3): 4(12.01) + 6(1.01) + 3(16.00) = 102.09 g/mol- Acetylsalicylic acid (C9H8O4): 9(12.01) + 8(1.01) + 4(16.00) = 180.16 g/molNext, let's calculate the number of moles of each reactant:- Moles of salicylic acid: 700 g / 138.12 g/mol = 5.07 mol- Moles of acetic anhydride: 80.0 g / 102.09 g/mol = 0.78 molNow, let's compare the mole ratio of the reactants to the stoichiometry of the reaction:- The reaction requires 2 moles of salicylic acid for every 1 mole of acetic anhydride.- The ratio of salicylic acid to acetic anhydride in the reaction is 2:1.Since we have 5.07 moles of salicylic acid and 0.78 moles of acetic anhydride, we can see that the ratio of salicylic acid to acetic anhydride is greater than the required ratio of 2:1. This means that acetic anhydride is the limiting reactant because it will be completely consumed before salicylic acid.Therefore, the limiting reactant is acetic anhydride.