19) through: (-5,-5) perp.to y=-(5)/(2)x A) y=-(1)/(5)x-3 B) y=-3x+(2)/(5) C) y=(1)/(5)x-3 D) y=(2)/(5)x-3

To find the equation of the line that passes through the point and is perpendicular to the line , we need to determine the slope of the perpendicular line.The slope of the given line is . The slope of a line perpendicular to this line is the negative reciprocal of , which is .Now, we can use the point-slope form of a linear equation to find the equation of the perpendicular line. The point-slope form is given by: where is a point on the line and is the slope.Substituting the point and the slope into the point-slope form, we get: Simplifying this equation, we have: Multiplying both sides by 5 to eliminate the fraction, we get: Expanding and simplifying further, we have: Dividing both sides by 5, we get: Therefore, the equation of the line that passes through the point and is perpendicular to the line is .The correct answer is D) .