8. A.145 kg baseball is pitched horizontally at 32.3m/s When a player hits the ball, it moves at the same speed, but in the opposite direction. If the bat and the ball are in contact for .0450 s, what is the magnitude of the average force from the bat on the ball? 9. A pitching machine throws two balls at a wall at the same speed Ball A is made of clay and sticks to the wall.Ball B is made of rubber and bounces off the wall.If both balls have the same mass, then which ball had the greater change in momentum from the collision with the wall? Explain your answer.

Question

8. A.145 kg baseball is pitched horizontally at 32.3m/s When a player hits the ball, it moves at the same speed, but in the opposite direction. If the bat and the ball are in contact for .0450 s, what is the magnitude of the average force from the bat on the ball? 9. A pitching machine throws two balls at a wall at the same speed Ball A is made of clay and sticks to the wall.Ball B is made of rubber and bounces off the wall.If both balls have the same mass, then which ball had the greater change in momentum from the collision with the wall? Explain your answer.

Answer 1

8. The magnitude of the average force from the bat on the ball can be calculated using the formula:Force = (Change in momentum) / (Time of contact)Given:Mass of the baseball = 0.145 kgInitial velocity of the baseball = 32.3 m/sFinal velocity of the baseball = -32.3 m/s (opposite direction)Time of contact = 0.0450 sChange in momentum = Final momentum - Initial momentumChange in momentum = (Mass * Final velocity) - (Mass * Initial velocity)Change in momentum = (0.145 kg * (-32.3 m/s)) - (0.145 kg * 32.3 m/s)Change in momentum = -4.66 kg*m/sForce = (Change in momentum) / (Time of contact)Force = (-4.66 kg*m/s) / (0.0450 s)Force = -103.56 NThe magnitude of the average force from the bat on the ball is 103.56 N.9. The change in momentum for each ball can be calculated using the formula:Change in momentum = Final momentum - Initial momentumFor Ball A (clay):Initial momentum = Mass * Initial velocityFinal momentum = 0 (since it sticks to the wall)Change in momentum = 0 - (Mass * Initial velocity)For Ball B (rubber):Initial momentum = Mass * Initial velocityFinal momentum = Mass * Final velocity (after bouncing off the wall)Change in momentum = (Mass * Final velocity) - (Mass * Initial velocity)Since both balls have the same mass, the change in momentum for Ball A is equal to the change in momentum for Ball B.Therefore, both balls had the same change in momentum from the collision with the wall.

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