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AMPLE: MPLE: No 5. Nirogeja and FydrogenTy. to Form Ammonla Gas According to the Following, Equation. Balance the Equation

Problemas

AMPLE: MPLE: No 5. Nirogeja and fydrogenTy. to form ammonla gas according to the following, equation. Balance the equation 1N_(2)+3H_(2)arrow 2NH_(3) a) 1456.0 grams of nitrogen are used up by the reaction, how many will be produced? underline (2) N_(2) +underline ( )H_(2) arrow underline ( )NH_(3) b) How many grams of hydrogen react if the reaction neesis to produce 63.5 grams of ammenia? underline ( )N_(2)+underline ( )H_(2)+NH_(3)

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Respuesta

a) To find out how many grams of ammonia will be produced when 1456.0 grams of nitrogen are used up by the reaction, we need to use the balanced chemical equation and the molar masses of the reactants and products.The balanced chemical equation is: First, we need to calculate the molar mass of nitrogen (N2) and ammonia (NH3):- Molar mass of N2 = 28.02 g/mol- Molar mass of NH3 = 17.03 g/molNext, we need to convert the mass of nitrogen to moles using its molar mass:Moles of N2 = 1456.0 g / 28.02 g/mol = 52.0 molesNow, we can use the stoichiometry of the balanced equation to find the moles of ammonia produced:1 mole of N2 produces 2 moles of NH352.0 moles of N2 will produce 2 * 52.0 = 104.0 moles of NH3Finally, we can convert the moles of ammonia to grams using its molar mass:Mass of NH3 = 104.0 moles * 17.03 g/mol = 1769.12 gramsTherefore, when 1456.0 grams of nitrogen are used up by the reaction, 1769.12 grams of ammonia will be produced.b) To find out how many grams of hydrogen react if the reaction needs to produce 63.5 grams of ammonia, we can use the balanced chemical equation and the molar masses of the reactants and products.The balanced chemical equation is: First, we need to calculate the molar mass of ammonia (NH3):- Molar mass of NH3 = 17.03 g/molNext, we need to convert the mass of ammonia to moles using its molar mass:Moles of NH3 = 63.5 g / 17.03 g/mol = 3.72 molesNow, we can use the stoichiometry of the balanced equation to find the moles of hydrogen reacted:1 mole of NH3 is produced from 3 moles of H23.72 moles of NH3 will be produced from 3.72 * 3 = 11.16 moles of H2Finally, we can convert the moles of hydrogen to grams using its molar mass:Molar mass of H2 = 2.02 g/molMass of H2 = 11.16 moles * 2.02 g/mol = 22.53 gramsTherefore, if the reaction needs to produce 63.5 grams of ammonia, 22.53 grams of hydrogen will react.