18. A 0.460 N force exists between two charges separated by 0.47 m. The first charge is 9.4 pC,what is the magnitude of the second charge? (1mu C=1times 10^-6C) square theoreman square Answer: 19. Two objects are separated by 6.5 km the first mass is 2.1times 10^kkg and the gravitabional force is 3.4 N, what is the mass of the second object? square square . Work: Answer: 1.0times 10^12kg 20.A 1.83times 10^10 V force exists between spheres charact 45C and 6.2 C. what is that square Formula: square Work: 4.3.7 m b. 14 m C. 12 m 437 a

Question

Answer 1

Let's solve the questions step by step:---### **18. Finding the magnitude of the second charge:**We use Coulomb's Law for this problem:

Where:-

(force between charges),-

(distance between charges),-

,-

(Coulomb's constant).Rearranging the formula to solve for

:

Substitute the values:

First, calculate

:

Now substitute into the equation:

So, the magnitude of the second charge is:

---### **19. Finding the mass of the second object:**We use Newton's law of gravitation:

Where:-

(gravitational force),-

(distance between objects),-

,-

(gravitational constant).Rearranging the formula to solve for

:

Substitute the values:

First, calculate

:

Now substitute into the equation:

Simplify the numerator:

Simplify the denominator:

Combine terms:

So, the mass of the second object is:

---### **20. Finding the distance between two charges:**We use Coulomb's Law again:

Where:-

(force between charges),-

,-

.Rearranging the formula to solve for

:

Substitute the values:

First, calculate the numerator:

Now divide by

:

Take the square root:

So, the distance between the charges is approximately:

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