Consider the combustion reaction for acetylene. 2C_(2)H_(2)(l)+5O_(2)(g)arrow 4CO_(2)(g)+2H_(2)O(g) If the acetylene tank contains 37.0 mol of C_(2)H_(2) and the oxygen tank contains 81.0 mol of O_(2) what is the limitin reactant for this reaction? O_(2) CO_(2) H_(2)O

To determine the limiting reactant, we need to compare the mole ratio of the reactants to the stoichiometric ratio in the balanced chemical equation.The balanced chemical equation for the combustion reaction of acetylene is: From the equation, we can see that the stoichiometric ratio of to is 2:5.Now, let's calculate the mole ratio of the reactants:Mole ratio of to = Since the mole ratio of to is less than the stoichiometric ratio, is the limiting reactant.Therefore, the limiting reactant for this reaction is .