7) A pulley has an efficiency of 85.0% If 475 J are exertedjo lift a 16.0 kg weight, how high is the weight lifted? 85=(wout)/(win)cdot 100

To solve this problem, we need to use the formula for efficiency and the given information to find the height the weight is lifted.Given information:- Efficiency of the pulley: 85.0%- Work input (W_in) = 475 J- Mass of the weight16.0 kgStep 1: Calculate the work output (W_out) using the efficiency formula.Efficiency = (W_out / W_in) × 10085.0% = (W_out / 475 J) × 100W_out = 0.85 × 475 JW_out = 403.75 JStep 2: Calculate the height the weight is lifted using the work-energy principle.Work done = Change in gravitational potential energyW_out = m × g × h403.75 J = 16.0 kg × 9.8 m/s² × hh = 403.75 J / (16.0 kg × 9.8 m/s²)h = 2.5 mTherefore, the weight is lifted 2.5 meters high.