Given a gas is at 22 Land 1 mol, what is the volume of the gas when the number of moles changes to 4 mol? Round to one decimal place. square

To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas, given that the temperature and pressure remain constant.The ideal gas law can be expressed as:PV = nRTWhere:P = PressureV = Volumen = Number of molesR = Ideal gas constantT = TemperatureGiven information:- Initial volume (V1) = 22 L- Initial number of moles (n1) = 1 mol- Final number of moles (n2) = 4 molWe need to find the final volume (V2) when the number of moles changes to 4 mol.Using the ideal gas law, we can write the equation for the initial and final states:P1V1 = n1RTP2V2 = n2RTSince the pressure and temperature remain constant, we can divide the two equations:P1V1 / P2V2 = n1 / n2Substituting the given values:22 L / V2 = 1 mol / 4 molSolving for V2:V2 = (22 L × 4 mol) / 1 molV2 = 88 LTherefore, the volume of the gas when the number of moles changes to 4 mol is 88.0 L (rounded to one decimal place).