Problemas
For a class project.Jerome builds a simple circuit with a battery and three light bulbs.On his way to school, Jerome drops his project and breaks one of the light bulbs. He has no time to fix or replace the bulb, so he removes the broken bulb and turns in his project. What will happen when Jerome runs current through his circuit? If Jerome built a series circuit, both remaining bulbs will still light up. If Jerome built a parallel circuit, both remaining bulbs will still light up. If Jerome built a series circuit, only the remaining bulb closest to the battery will light up If Jerome built a parallel circuit, only the remaining bulb closest to the battery will light up.
Roztwór
Esperanza
élite · Tutor durante 8 años
4
(241 Votos)
Respuesta
B
Explicación
## Step 1The problem involves understanding the behavior of electrical circuits, specifically series and parallel circuits. In a series circuit, the current flows through each component sequentially. If one component (like a light bulb) is removed or broken, the circuit is broken, and no current can flow. Therefore, in a series circuit, if one bulb is removed, none of the bulbs will light up.## Step 2In a parallel circuit, each component is connected across the same two points, creating multiple paths for the current to flow. If one component is removed or broken, the current can still flow through the other paths. Therefore, in a parallel circuit, if one bulb is removed, the remaining bulbs will still light up.## Step 3Given these principles, the correct answer is that if Jerome built a parallel circuit, both remaining bulbs will still light up.