2KClO_(3)arrow 2KCl+3O_(2) If there are 45.82gKClO_(3) how many grams of O_(2) are made? (mmKClO_(3)=122g/mol)(mmO_(2)=32g/mol) 18.03 g KCI 59.028 KCI 27.21 g KCl 264920 g KCl

To solve this problem, we need to use the concept of stoichiometry and the molar mass of the substances involved.Given information:- The balanced chemical equation is: - The mass of is - The molar mass of is - The molar mass of is Step 1: Calculate the number of moles of .Number of moles of = Mass of / Molar mass of Number of moles of = Step 2: Use the stoichiometric relationship between and to find the number of moles of produced.According to the balanced equation, 2 moles of produce 3 moles of .Number of moles of produced = Step 3: Calculate the mass of produced.Mass of = Number of moles of × Molar mass of Mass of = Therefore, the correct answer is:18.03 g