1. A 4600 kg helicopter accelerates upward at 2.0m/s^2 What lift force is exerted by the air on the propellors?

To solve this problem, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.Given information:- Mass of the helicopter, m = 4600 kg- Acceleration of the helicopter, a = 2.0 m/s² (upward)The lift force exerted by the air on the propellers can be calculated using the formula:Lift force = Mass × (Acceleration due to gravity + Acceleration of the helicopter)The acceleration due to gravity is approximately 9.8 m/s².Substituting the values, we get:Lift force = 4600 kg × (9.8 m/s² + 2.0 m/s²)Lift force = 4600 kg × 11.8 m/s²Lift force = 54,320 NTherefore, the lift force exerted by the air on the propellers is 54,320 N.