How m For the following reaction: 2F_(2(g))+C_(2)H_(2(g))arrow C_(2)H_(2)F_(4(l)) How many liters of fluorine will be needed to make 45 grams of C_(2)H_(2)F_(4) (molar mass C_(2)H_(2)F_(4)=102.0298g/mol)

Question

Answer 1

To determine how many liters of fluorine (

) are needed to make 45 grams of

, we need to follow these steps:1. **Calculate the moles of

:** Given: - Mass of

= 45 grams - Molar mass of

= 102.0298 g/mol Moles of

=

2. **Determine the stoichiometry of the reaction:** The balanced chemical equation is:

From the equation, 1 mole of

is produced from 2 moles of

.3. **Calculate the moles of

needed:** Since 1 mole of

requires 2 moles of

:

4. **Convert moles of

to liters:** At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.

Therefore, approximately 19.75 liters of fluorine (

) are needed to make 45 grams of

.

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